X=2x^2+14x

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Solution for X=2x^2+14x equation:



X=2X^2+14X
We move all terms to the left:
X-(2X^2+14X)=0
We get rid of parentheses
-2X^2+X-14X=0
We add all the numbers together, and all the variables
-2X^2-13X=0
a = -2; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·(-2)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*-2}=\frac{0}{-4} =0 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*-2}=\frac{26}{-4} =-6+1/2 $

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